0=1+2.4x-4.9x^2

Solution for 0=1+2.4x-4.9x^2 equation:

0=1+2.4x-4.9x^2

We move all terms to the left:

0-(1+2.4x-4.9x^2)=0

We add all the numbers together, and all the variables

-(1+2.4x-4.9x^2)=0

We get rid of parentheses

4.9x^2-2.4x-1=0

a = 4.9; b = -2.4; c = -1;
Δ = b2-4ac
Δ = -2.42-4·4.9·(-1)
Δ = 25.36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2.4)-\sqrt{25.36}}{2*4.9}=\frac{2.4-\sqrt{25.36}}{9.8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2.4)+\sqrt{25.36}}{2*4.9}=\frac{2.4+\sqrt{25.36}}{9.8}
$